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A gas expands isothermally against a constant external pressure of 1 atm from a volume of 10 dm^3 to a volume of 20 dm^3.

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A gas expands isothermally against a constant external pressure of 1 atm from a volume of 10 dm3 to a volume of 20 dm3. It absorbs 300 J of thermal energy from its surrounding. The ΔU is:

(a) – 312 J

(b) + 123 J

(c) – 213 J

(d) + 231 J

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(c) – 213 J

Explanation:

W = -∫V2 V1PdV = -P(V2 - V1)

W = –(1 atm) (20 – 10) = –10 dm3 atm.

= -10dm3 x 8.314 J/K/mol/ 0.08206dm3 /K/mol

= -1013J

According to Ist law of thermodynamics,

ΔU = q + W = 800J + (–1013 J) = –213 J

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