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29/09/2021 12:00 pm
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What is Δngas for the combustion of 1 mole of benzene, when both the reactants and the products are at 298 K?
(a) 0
(b) 1/2
(c) 3/2
(d) -3/2
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29/09/2021 12:06 pm
Correct answer: (d) -3/2
Explanation:
C6H6(l) + \(\frac{15}{2}\)O2(g) → 6CO2(g) + 3H2O(l)
Δn = 6 - \(\frac{15}{2}\)
= - \(\frac{3}{2}\)