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30/09/2021 11:03 am
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The standard Gibb’s free energy change, ΔG° is related to equilibrium constant, KP as
(a) KP = -RT ln ΔG°
(b) KP = \(\Big[ \frac{e}{RT}\Big]^{\Delta G°}\)
(c) KP = -\(\frac{\Delta G}{RT}\)
(d) KP = eΔG°/RT
1 Answer
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30/09/2021 11:05 am
Correct answer: (d) KP = eΔG°/RT
Explanation:
ΔG = -RT ln KP or KP = eΔG°/RT