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29/09/2021 11:28 am
Topic starter
The (S°) of the following substances are:
CH4 (g) 186.2 JK–1 mol–1
O2 (g) 205.2 JK–1 mol–1
CO2(g) 213.6 JK–1 mol–1
H2O(g) 69.9.JK–1 mol–1
The entropy change (ΔS°) for the reaction
CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) is:
(a) -312.5 J K–1 mol–1
(b) -242.8 J K–1 mol–1
(c) -108.1 J K–1 mol–1
(d) -37.6 J K–1 mol–1
1 Answer
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29/09/2021 11:32 am
Correct answer: (b) -242.8 J K–1 mol–1
Explanation:
ΔS° = S°CO2 + 2 x S°H2O - (S°CH4 + 2 x S°O2)
= (213.6 + 2 × 69.9) – (186.2 + 2 × 205.2)
= -242.8 J K–1 mol–1