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30/09/2021 11:24 am
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The molar enthalpies of combustion of isobutane and n-butane are -2870 kJ mol-1 and –2875 kJ mol-1 respectively at 298 K and 1 atm. Calculate ΔHº for the conversion of 1 mole of n-butane to 1 mole of isobutane
(a) -8 kJ mol-1
(b) +8 kJ mol-1
(c) -5748 kJ mol-1
(d) +5748 kJ mol-1
1 Answer
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30/09/2021 11:29 am
Correct answer: (a) -8 kJ mol-1
Explanation:
Isobutane + oxygen → CO2 + H2O
ΔH = -2870 kJ mol-1 .....(i)
n-butane oxygen → CO2 + H2O
(ii) – (i); n-butane – Isobutane,
ΔH = (-2878 + 2870)
= -8 kJ mol-1.