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01/10/2021 11:44 am
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The heat of atomization of PH3(g) is 228 kcal mol-1 and that of P2H4(g) is 335 kcal mol-1. The energy of the P–P bond is
(a) 102 kcal mol-1
(b) 51 kcal mol-1
(c) 26 kcal mol-1
(d) 204 kcal mol-1
1 Answer
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01/10/2021 11:48 am
Correct answer: (b) 51 kcal mol-1
Explanation:
Bond dissociation energy of
PH3(g) = 228 kcal mol-1
P – H bond energy = \(\frac{228}{3}\)
= 76 kcal mol-1
Bond energy of 4 (P – H) + (P –P)
= 355 kcal mol-1
or 4 × 76 + (P – P) = 355 kcal mol-1
P–P bond energy = 51 kcal mol-1