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30/09/2021 10:31 am
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The favourable conditions for a spontaneous reaction are
(a) TΔS > ΔH, ΔH = +ve, ΔS = +ve
(b) TΔS > ΔH, ΔH = +ve, ΔS = -ve
(c) TΔS = ΔH, ΔH = -ve, ΔS = -ve
(d) TΔS = ΔH, ΔH = +ve, ΔS = +ve
1 Answer
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30/09/2021 10:55 am
Correct answer: (a) TΔS > ΔH, ΔH = +ve, ΔS = +ve
Explanation:
ΔG = ΔH - TΔS, ΔH is +ve,
ΔS is +ve; TΔS > ΔH
for spontaneous process.
It will make ΔG, –ve