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29/09/2021 12:34 pm
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The entropy of a sample of a certain substance increases by 0.836 J K-1 on adding reversibly 0.3344 J of heat at constant temperature. The temperature of the sample is:
(a) 2.5 K
(b) 0.3 K
(c) 0.016 K
(d) 0.4 K
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29/09/2021 12:38 pm
Answer: (d) 0.4 K
Explanation:
ΔS = \(\frac{\Delta H}{T}\)
T = \(\frac{\Delta H}{\Delta S}\)
= \(\frac{0.3344}{0.836}\)
= 0.4K
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