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29/09/2021 11:38 am
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The enthalpy of the reaction forming PbO according to the following equation is 438 kJ. What heat energy (kJ) is released in formation of 22.3 g PbO(s)? (Atomic masses : Pb = 207, O = 16.0)
2Pb(s) + O2(g) → 2PbO(s)
(a) 21.9
(b) 28.7
(c) 14.6
(d) 34.2
1 Answer
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29/09/2021 11:39 am
Correct answer: (a) 21.9
Explanation:
Q = \(\frac{1}{2}\)438 x \(\frac{22.3}{223}\)
= 21.9 kJ