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26/09/2021 12:31 pm
Topic starter
The difference between the reaction enthalpy change (ΔrH) and reaction internal energy change (ΔrU) for the reaction:
2C6H6(l) + 15O2(g) → 12CO2(g) + 6H2O(l)
at 300 K is (R = 8.314 J mol-1K-1)
(a) 0 J mol-1
(b) 2490 J mol-1
(c) –2490 J mol-1
(d) –7482 J mol-1
1 Answer
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26/09/2021 12:34 pm
Correct answer: (d) –7482 J mol-1
Explanation:
ΔH = ΔU + ΔngRT
For the reaction
Δng = 12 - 15 = -3
ΔH – ΔU = – 3 × 8.314 × 300
= -7482 J mol-1