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03/10/2021 11:51 am
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Temperature of 5 moles of a gas is decreased by 2K at constant pressure. Indicate the correct statement
(a) Work done by gas is = 5 R
(b) Work done over the gas is = 10 R
(c) Work done by the gas = 10 R
(d) Work done = 0
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03/10/2021 11:55 am
Correct answer: (b) Work done over the gas is = 10 R
Explanation:
For 5 moles of gas at temperature T,
PV1 = 5RT
For 5 moles of gas at temperature T - 2,
PV2 = 5R(T – 2)
∴ P(V2 - V1) = 5R(T – 2 – T);
PΔV = – 10R,
-PΔV = 10R
When ΔV is negative, W is + ve.