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01/10/2021 11:01 am
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One mole of solid iron was vaporized in an oven at its boiling point of 3433 K and enthalpy of vaporization of iron is 344.3 kJ mol-1. The value of entropy vaporization (in J mol-1) of iron is
(a) 100
(b) 10
(c) -100
(d) 110
1 Answer
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01/10/2021 11:03 am
Correct answer: (a) 100
Explanation:
ΔS = \(\frac{ΔH}{T}\)
= \(\frac{344.3 \times 10^3}{3443}\)
= 100 J mol-1