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29/09/2021 12:41 pm
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One mole of an ideal gas is expanded isothermally and reversibly to half of its initial pressure. ΔS for the process in J K–1 mol–1 is [ℓn 2 = 0.693 and R = 8.314, J/(mol K)]
(a) 6.76
(b) 5.76
(c) 10.76
(d) 8.03
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29/09/2021 12:44 pm
Correct answer: (b) 5.76
Explanation:
For isothermal process (ΔT = 0)
ΔS = R ℓn \(\frac{P_1}{P_2}\) = 8.314 ℓn 2
= 8.314 x 0.693 = 5.76