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One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K) → (4.0 atm, 5.0 L, 245 K) with a change in internal energy, ΔU = 30.0 L atm. The change in enthalpy ΔH of the process in L atm is

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One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K) → (4.0 atm, 5.0 L, 245 K) with a change in internal energy, ΔU = 30.0 L atm. The change in enthalpy ΔH of the process in L atm is

(a) 40.0

(b) 42.3

(c) 44.0

(d) Not defined because pressure is not constant

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Correct answer: (c) 44.0

Explanation:

ΔH = H2 - H1 = (E2 + P2V2) - (E1 + P1V1)

= (E2 - E1) + (P2V2 - P1V1)

= 30 + (4 x 5 - 2 x 3) = 44 L atm

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