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24/09/2021 3:06 pm
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Heat of neutralization of a strong acid HA and a weaker acid HB with KOH are –13.7 and – 12.7 k cal mol-1. When 1 mole of KOH was added to a mixture containing 1 mole each of HA and HB, the heat change was – 13.5 kcal. In what ratio is the base distributed between HA and HB.
(a) 3 : 1
(b) 1 : 3
(c) 4 : 1
(d) 1 : 4
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24/09/2021 3:16 pm
Correct answer: (c) 4 : 1
Explanation:
Let x mole of KOH be neutralized by the strong acid HA. Then, moles neutralized by HB = 1 – x
Hence, -13.7 × x + (-12.7) × (1 – x) = -13.5
⇒ x = 0.8; \(\frac{x}{1 - x}\) = \(\frac{0.8}{0.2}\)
= \(\frac{4}{1}\) = 4 : 1