From given following equations and ΔH° values, determine the enthalpy of reaction at 298 K for the reaction:

C₂H₄(g) + 6F₂(g) → 2CF₄(g) + 4HF(g)

H₂(g) + F₂(g) → 2HF(g); ΔH°₁ = -537 kJ

C(s) + 2F₂(g) → CF₄(g); ΔH°₂ = -680 kJ

2C(s) + 2H₂(g) → C₂H₄(g); ΔH°₃ = 52 kJ

(a) -1165

(b) -2486

(c) +1165

(d) +2486