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For the reaction C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l) at constant temperature, ΔH - ΔE is

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For the reaction

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l)

at constant temperature, ΔH - ΔE is

(a) -RT

(b) +RT

(c) -3 RT

(d) +3 RT

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Correct answer: (c) -3 RT

Explanation:

ΔH = ΔE + ΔnRT

Δn = 3 - (1 + 5)

= 3 - 6 = -3

ΔH - ΔE = (-3RT)

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