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01/10/2021 11:14 am
Topic starter
For the reaction
2C6H5CO2H(s) + 15O2(g) → 14CO2(g) + 6H2O(g)
ΔUº = -772.7 kJ mol-1 at 298 K. Calculate ΔHº
(a) +760.3 kJ mol-1
(b) -760.3 kJ mol-1
(c) +670.3 kJ mol-1
(d) -790.3 kJ mol-1
1 Answer
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01/10/2021 11:16 am
Correct answer: (b) -760.3 kJ mol-1
Explanation:
ΔHº = ΔUº + ΔnRT
ΔHº = -772.7 + \(\frac{5 \times 8.314 \times 298}{1000}\)
= -760.3 kJ mol-1