1 gram equivalent of H2SO4 is treated with 112 g of KOH for complete neutralization. Which of the following statements is correct?
(a) 13.7 kcal of heat is evolved with the formation of 87 g of K2SO4, leaving no KOH.
(b) 27.4 kcal of heat is evolved with the formation of 87 g of K2SO4, leaving 4 gram equivalent of KOH.
(c) 15.7 kcal of heat is evolved with the formation of 1 gram equivalent of K2SO4, leaving 56 g of KOH.
(d) 13.7 kcal of heat is evolved with the formation of 87g of K2SO4, leaving 1 gram equivalent of KOH.
Correct answer: (d) 13.7 kcal of heat is evolved with the formation of 87g of K2SO4, leaving 1 gram equivalent of KOH.
Explanation:
H2SO4 + 2KOH → K2SO4 + 2H2O
98 112 174 2 Mole
49 56 87 1 mole
13.7 kcal is the heat evolved when 1 gev of strong acid is neutralised by 1 gev of strong base.