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In a compound, nitrogen atoms (N) make cubic close packed lattice and metal atoms (M) occupy one-third of the tetrahedral voids present.

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In a compound, nitrogen atoms (N) make cubic close packed lattice and metal atoms (M) occupy one-third of the tetrahedral voids present. Determine the formula of the compound formed by M and N?

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In ccp, no. of atoms per unit cell = 4

Thus, of tetrahedral voids = 2 x No. of atoms in ccp = 2 x 4 = 8

Only one-third of tetrahedral voids are occupied by metal M.

No. of metal atoms, M = 1/3 x 8

M:N = 8/3 : 4 = 2 : 3

Thus, formula is M2N3.

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