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Find the number of voids in 0.2 moles of a compound forming hexagonal close-packed structure. What number of these are tetrahedral voids?

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Find the number of voids in 0.2 moles of a compound forming hexagonal close-packed structure. What number of these are tetrahedral voids?

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Given, No. of close-packed particles = 0.2 × 6.022 × 1023 = 1.2044 × 1023

Thus, no. of octahedral voids = 1.2044 × 1023

And, no. of tetrahedral voids = 2 × 1.2044 × 1023 = 2.4088 × 1023

Thus, total number of voids = 1.2044 × 1023 + 2.4088 × 1023 = 3.6132 × 1023

This post was modified 5 years ago 2 times by nikhil04
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