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If NaOH is added to an aqueous solution of Zn^2+ ions, a white precipitate appears and on adding excess NaOH, the precipitate dissolves. In this solution zinc exists in the

The s-Block Elements

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25/12/2021 1:42 pm

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Palak23

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If NaOH is added to an aqueous solution of Zn²⁺ ions, a white precipitate appears and on adding excess NaOH, the precipitate dissolves. In this solution zinc exists in the

(a) both in cationic and anionic parts

(b) there is no zinc left in the solution

(d) anionic part.

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25/12/2021 1:46 pm

Reyana09

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Correct answer: (d) anionic part.

Explanation:

Zn²⁺+ 2NaOH → Zn(OH)₂ + 2Na⁺

Zn(OH)₂ + 2NaOH → Na₂ZnO₂ + 2H₂O

Na₂ZnO₂ → 2Na⁺+ (ZnO₂)^2-

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If NaOH is added to an aqueous solution of Zn^2+ ions, a white precipitate appears and on adding excess NaOH, the precipitate dissolves. In this solution zinc exists in the

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