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(Si2O5)n^2n- anion is obtained when

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(Si2O5)n2n- anion is obtained when

(a) no oxygen of a SiO44- tetrahedron is shared with another SiO44- tetrahedron

(b) one oxygen of a SiO44- tetrahedron is shared with another SiO44- tetrahedron

(c) two oxygen of a SiO44- tetrahedron are shared with another SiO44- tetrahedron

(d) three oxygen of a SiO44- tetrahedron are shared with another SiO44- tetrahedron

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Correct answer: (d) three oxygen of a SiO44- tetrahedron are shared with another SiO44- tetrahedron

Explanation:

Total No. oxygen atoms per silicon atom

= \(\frac{1}{2}\) + \(\frac{1}{2}\) + \(\frac{1}{2}\) + 1 = 2.5

∴ Formula Si2O52-

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