Notifications
Clear all
Ge(II)compounds are powerful reducing agents whereas Pb(IV) compounds are strong oxidants. It is because
0
02/01/2022 3:24 pm
Topic starter
Ge(II)compounds are powerful reducing agents whereas Pb(IV) compounds are strong oxidants. It is because
(a) Pb is more electropositive than Ge
(b) ionization potential of lead is less than that of Ge
(c) ionic radii of Pb2+ and Pb4+ are larger than those of Ge2+ and Ge4+
(d) of more pronounced inert pair effect in lead than in Ge
Answer
Add a comment
Add a comment
Topic Tags
1 Answer
0
02/01/2022 3:25 pm
Correct answer: (d) of more pronounced inert pair effect in lead than in Ge
Explanation:
Ge(II) tends to acquire Ge (IV) state by loss of electrons. Hence it is reducing in nature. Pb (IV) tends to acquire Pb (II) O.S. by gain of electrons. Hence it is oxidising in nature. This is due to inert pair effect.
Add a comment
Add a comment
Forum Jump:
Related Topics
-
The shape of gaseous SnCl2 is
3 years ago
-
Which of the following is/are not correctly matched? (i) GeO2 – Acidic (ii) PbO2 – Amphoteric (iii) CO – Neutral
3 years ago
-
When steam reacts with red hot coke to form CO2 and hydrogen
3 years ago
-
The structure and hybridization of Si(CH3)4 is
3 years ago
-
A solid element (symbol Y) conducts electricity and forms two chlorides YCln (colourless volatile liquid) and YCln-2 (a colourless solid).
3 years ago
Forum Information
- 321 Forums
- 27.3 K Topics
- 53.8 K Posts
- 26 Online
- 12.4 K Members
Our newest member: Stripchat
Forum Icons:
Forum contains no unread posts
Forum contains unread posts
Topic Icons:
Not Replied
Replied
Active
Hot
Sticky
Unapproved
Solved
Private
Closed