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Ge(II)compounds are powerful reducing agents whereas Pb(IV) compounds are strong oxidants. It is because

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Ge(II)compounds are powerful reducing agents whereas Pb(IV) compounds are strong oxidants. It is because

(a) Pb is more electropositive than Ge

(b) ionization potential of lead is less than that of Ge

(c) ionic radii of Pb2+ and Pb4+ are larger than those of Ge2+ and Ge4+

(d) of more pronounced inert pair effect in lead than in Ge

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Correct answer: (d) of more pronounced inert pair effect in lead than in Ge

Explanation:

Ge(II) tends to acquire Ge (IV) state by loss of electrons. Hence it is reducing in nature. Pb (IV) tends to acquire Pb (II) O.S. by gain of electrons. Hence it is oxidising in nature. This is due to inert pair effect.

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