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AlI3, when reacts with CCl4, gives

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AlI3, when reacts with CCl4, gives

(a) AlCl3

(b) CI4

(c) Al4C3

(d) both (a) and (b)

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Correct answer: (d) both (a) and (b)

Explanation:

AlI3, on reaction with CCl4, gives the AlCl3

4AlI3 + 3CCl4 → 4Al4C3 + 3CI4

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