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What is short-sightedness? State the two causes of short-sightedness (or myopia). With the help of ray diagrams, show: 1. the eye-defect short-sightedness. 2. correction of short-sightedness by using a lens

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(a) What is short-sightedness? State the two causes of short-sightedness (or myopia). With the help of ray diagrams, show:

1. the eye-defect short-sightedness.

2. correction of short-sightedness by using a lens.

(b) A person having short-sight cannot see objects clearly beyond a distance of 1.5 m. What would be the nature and power of the corrective lens to restore proper vision?

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(a) Short Sightedness is that defect of vision due to which a person can see nearby objects clearly but cannot see distant objects clearly.

Causes:

1. Excessive curvature of the eye lens

2. Elongation of the eyeball

Ray diagram for:

(i) eye-defect short sightedness

In a myopic eye, image of distant object is formed in front of the retina (and not on the retina)
The far point (F) of a myopic eye is less than infinity
(ii) Correction of short-sightedness by using a lens
Correction of myopia. The concave lens placed in front of the eye forms a virtual image of distant object at far point (F) of the myopic eye.

(b) Concave lens should be used to restore proper vision.

Calculation of power of the lens:

Here, far point of myopic = 1.5 m

The object kept at infinity can be seen clearly if the image of this object is formed at 1.5 m.

So, object distance, u = ∞

Image distance, v = 1.5 m

\(\frac{1}{v}\) - \(\frac{1}{u}\) = \(\frac{1}{f}\)

\(\frac{1}{-1.5}\) - \(\frac{1}{ ∞}\) = \(\frac{1}{f}\)

f = 1.5 m

P = \(\frac{1}{f}\) = \(\frac{1}{-1.5}\)

= -0.67 D

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