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30/09/2020 4:51 pm
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The electrons, identified by quantum numbers n and l (i) n = 4, l = 1 (ii) n = 4, l = 0 (iii) n = 3, l = 2 (iv) n = 3, l = 1 can be placed in order of increasing energy, from the lowest to highest, as
(a) (iv) < (ii) < (iii) < (i)
(b) (ii) < (iv) < (i) < (iii)
(c) (i) < (iii) < (ii) < (iv)
(d) (iii) < (i) < (iv) < (ii)
1 Answer
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30/09/2020 4:54 pm
(a) (iv) < (ii) < (iii) < (i)
Explanation:
(n + l) rule the higher the value of (n + l), the higher is the energy. When (n + l) value is the same see value of n.
i ii iii iv
(n + l) (4 + 1) (4 + 0) (3 + 2) (3 + 1)
5 4 5 4
(iv) < (ii) < (iii) < (i)