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Let mp be the mass of a proton, mn that of a neutron, M1 that of a 20^10Ne nucleus and M2 that of a 40^20Ca nucleus. Then

Structure of Atom

Last Post by Freddie12 4 years ago

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01/10/2020 10:49 am

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Shaneylee18

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Let m_p be the mass of a proton, m_n that of a neutron, M₁ that of a ²⁰₁₀Ne nucleus and M₂ that of a ⁴⁰₂₀Ca nucleus. Then

(a) M₂ = 2M₁

(b) M₁ < 10(m_p + m_n)

(d) M₁ = M₂

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01/10/2020 10:56 am

Freddie12

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(a) M₂ = 2M₁

Explanation:

²⁰₁₀Ne contains 10 protons and 10 neutrons

∴ M₁ = 10m_p + 10m_n

⁴⁰₂₀Ca contains 20 protons and 20 neutrons

∴ M₂ = 20m_p + 20m_n

∴ M₂ = 2M₁

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Let mp be the mass of a proton, mn that of a neutron, M1 that of a 20^10Ne nucleus and M2 that of a 40^20Ca nucleus. Then

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