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18/08/2021 10:39 am
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Which combinations of quantum numbers, n, l, m and s for the electron in an atom does not provide a permissible solution of the wave equation?
(a) 3, 2, 1, +\(\frac{1}{2}\)
(b) 3, 1, 1, -\(\frac{1}{2}\)
(c) 3, 3, 1, -\(\frac{1}{2}\)
(d) 3, 2, -2, +\(\frac{1}{2}\)
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18/08/2021 10:42 am
Correct answer: (c) 3, 3, 1, -\(\frac{1}{2}\)
Explanation:
Possible values of l and m depend upon the value of n
l = 0 to (n – 1)
m = –l to + l through zero
s = +\(\frac{1}{2}\) and - \(\frac{1}{2}\)
Thus for n = 3,
l may be 0, 1 or 2; but not 3
m may be –2, –1, 0, +1 or +2
s may be +\(\frac{1}{2}\) or - \(\frac{1}{2}\)