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16/08/2021 10:20 am
Topic starter
What is the maximum wavelength line in the Lyman series of He+ ion?
(a) 3R
(b) \(\frac{1}{3R}\)
(c) \(\frac{4}{4R}\)
(d) None of these
1 Answer
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16/08/2021 10:25 am
Correct answer: \(\frac{1}{3R}\)
Explanation:
\(\frac{1}{\lambda}\) = RZ2\(\big[\frac{1}{n_1^2} - \frac{1}{n_2^2} \big]\)
= R x 22\(\big[\frac{1}{1^2} - \frac{1}{2^2} \big]\)
⇒ 3R; \(\lambda = \frac{1}{3R}\)