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16/08/2021 10:15 am
Topic starter
The wave number of the first emission line in the Balmer series of H-Spectrum is
(R = Rydberg constant) :
(a) \(\frac{5}{36}\)R
(b) \(\frac{9}{400}\)R
(c) \(\frac{7}{6}\)R
(d) \(\frac{3}{4}\)R
1 Answer
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16/08/2021 10:18 am
Correct answer: (a) \(\frac{5}{36}\)R
Explanation:
\(\bar{v} = RZ^2(\frac{1}{2^2}- \frac{1}{3^2})\)
= R(\(\frac{1}{4} - \frac{1}{9}\))
= \(\frac{5}{36}\)R