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The Li^2+ ion is moving in the third stationary state, and its linear momentum is 7.3 × 10^–34 kgms^–1. Angular momentum is

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The Li2+ ion is moving in the third stationary state, and its linear momentum is 7.3 × 10–34 kgms–1. Angular momentum is.

(a) 1.158 × 10–45 kg m2 s–1

(b) 11.58 × 10–48 kg m2 s–1

(c) 11.58 × 10–47 kg m2 s–1

(d) 12 × 10–45 kg m2s–1

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Correct answer: (b) 11.58 × 10–48 kg m2 s–1

Explanation:

Z = 3 for Li2+ ions

So rn = \(\frac{52.9 \times n^2}{Z}\)pm

n = 3, Z = 3

rn = \(\frac{52.9 \times 3^2}{3}\) pm

= 158.7 pm

Also, linear momentum (mv) = 7.3 × 10–34 kgms–1

Then angular momentum will be

ω = mv x v

= (7.3 × 10–34 kgms–1)(158.7 pm) 

= 7.3 × 10–34 kgms–1 x 158.7 x 10–12m

= 11.58 × 10–48 kg m2 s–1

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