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18/08/2021 10:29 am
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The kinetic and potential energy (in eV) of an electron present in third Bohr's orbit of hydrogen atom are respectively:
(a) –1.51, –3.02
(b) 1.51, –3.02
(c) –3.02, 1.51
(d) 1.51, –1.51
1 Answer
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18/08/2021 10:31 am
Correct answer: (b) 1.51, –3.02
Explanation:
Total energy of third shell = \(\frac{-13.6}{3^2}\)
= -1.51 eV
K.E. = - Total energy ⇒ 1.51 eV
P.E. = 2 x T.E = -3.02 eV