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15/08/2021 11:22 am
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The energy of an electron in first Bohr orbit of Hatom is -13.6 eV. The energy value of electron in the excited state of Li2+ is:
(a) -27.2 eV
(b) 30.6 eV
(c) -30.6 eV
(d) 27.2 eV
1 Answer
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15/08/2021 11:25 am
Correct answer: (c) -30.6 eV
Explanation:
For Li2+ ion
E = -13.6 x \(\frac{Z^2}{n^2}\)
= -13.6 x \(\frac{3^2}{2^2}\)
= \(\frac{-13.6 \times 9}{4}\)
= -30.6 eV