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19/08/2021 12:39 pm
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The dissociation energy of H2 is 430.53 kJmol–1. If hydrogen is dissociated by illumination with radiation of wavelength 253.7 nm the fraction of the radiant energy which will be converted into kinetic energy is given by
(a) 100%
(b) 8.82%
(c) 2.22%
(d) 1.22%
1 Answer
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19/08/2021 12:44 pm
Correct answer: (b) 8.82%
Explanation:
Energy of 1 mole of photons,
E = N0 x hv
= \(\frac{N_0 \times h \times c}{\lambda}\)
= \(\frac{6.023 \times 10^{23} \times 6.63 \times 10^{-34} \times 3 \times 10^8}{253.7 \times 10^{-9}}\)
Energy converted into KE = (472.2 – 430.53) kJ % of energy converted into
KE = \(\frac{(472.2 - 430.53}{472.2}\) x 100
= 8.82%