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Let mp be the mass of a proton, mn that of a neutron, M1 that of a 20^10Ne nucleus and M2 that of a 40^20Ca nucleus. Then

Structure of Atom

Last Post by Shivani siva 3 years ago

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19/08/2021 11:51 am

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Deepak Rock

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Let m_p be the mass of a proton, m_n that of a neutron, M₁ that of a ²⁰₁₀Ne nucleus and M₂ that of a ⁴⁰₂₀Ca nucleus. Then

(a) M₂ = 2M₁

(b) M₁ < 10(m_p + m_n)

(d) M₁ = M₂

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19/08/2021 11:57 am

Shivani siva

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Correct answer: (a) M₂ = 2M₁

Explanation:

²⁰₁₀Ne contains 10 protons and 10 neutron

∴ M₁ = 10m_p + 10m_n

⁴⁰₂₀Ca contains 20 protons and 20 neutrons

∴ M₂ = 20m_p + 10m_n

∴ M₂ = 2M₁

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Let mp be the mass of a proton, mn that of a neutron, M1 that of a 20^10Ne nucleus and M2 that of a 40^20Ca nucleus. Then

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