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18/08/2021 11:05 am
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In a multi-electron atom, which of the following orbitals described by the three quantum members will have the same energy in the absence of magnetic and electric fields?
(A) n = 1, l = 0, m = 0
(B) n = 2, l = 0, m = 0
(C) n = 2, l = 1, m = 1
(D) n = 3, l = 2, m = 1
(E) n = 3, l = 2, m = 0
(a) (D) and (E)
(b) (C) and (D)
(c) (B) and (C)
(d) (A) and (B)
1 Answer
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18/08/2021 11:06 am
Correct answer: (a) (D) and (E)
Explanation:
The energy of an orbital is given by (n + l). In (D) and (E), (n + l) value is (3 + 2) = 5, hence they will have same energy, since here n values are also same.