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16/08/2021 11:20 am
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In a hydrogen atom, if energy of an electron in ground state is 13.6. ev, then that in the 2nd excited state is
(a) 1.51 eV
(b) 3.4 eV
(c) 6.04 eV
(d) 13.6 eV
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16/08/2021 11:23 am
Correct answer: (a) 1.51 eV
Explanation:
2nd excited state will be the 3rd energy level.
En = \(\frac{13.6}{n^2}\)eV
E = \(\frac{13.6}{9}\)eV = 1.51 eV