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20/08/2021 10:27 am
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If the subsidiary quantum number of a sub energy level is 4, the maximum and minimum values of the spin multiplicities are :
(a) 9, 1
(b) 10, 1
(c) 10, 2
(d) 4, –4
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20/08/2021 10:29 am
Correct answer: (c) 10, 2
Explanation:
l = 4
number of degenerate orbitals = 2l + 1 = 9
maximum total spins = 9 x \(\frac{1}{2}\)
maximum multiplicity = 2s + 1
= 2 x \(\frac{9}{2}\) + 1 = 10
minimum total spins = \(\frac{1}{2}\)
minimum multiplicity = 2 x \(\frac{1}{2}\) + 1 = 2