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17/08/2021 11:38 am
Topic starter
If the de-Broglie wavelength of a particle of mass m is 100 times its velocity, then its value in terms of its mass (m) and Planck’s constant (h) is
(a) \(\frac{1}{10}\)\(\sqrt{\frac{m}{h}}\)
(b) \(10\sqrt{\frac{h}{m}}\)
(c) \(\frac{1}{10}\)\(\sqrt{\frac{h}{m}}\)
(d) \(10\sqrt{\frac{m}{h}}\)
1 Answer
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17/08/2021 11:41 am
Correct answer: (b) \(10\sqrt{\frac{h}{m}}\)
Explanation:
Let wavelength of particle be x
So, velocity (v) = \(\frac{x}{100}\)
λ = \(\frac{h}{mv}\); x = \(\frac{h \times 100}{m \times x}\)
\(x^2 = 100 \frac{h}{m}\) or
x = \(10\sqrt{\frac{h}{m}}\)