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15/08/2021 12:24 pm
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If m and e are the mass and charge of the revolving electron in the orbit of radius r for hydrogen atom, the total energy of the revolving electron will be:
(a) \(\frac{1}{2}\)\(\frac{e^2}{2r}\)
(b) -\(\frac{e^2}{r}\)
(c) \(\frac{me^2}{r}\)
(d) -\(\frac{1}{2}\)\(\frac{e^2}{r}\)
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15/08/2021 12:28 pm
(d) -\(\frac{1}{2}\)\(\frac{e^2}{r}\)
Explanation:
Total energy of a revolving electron is the sum of its kinetic and potential energy.
Total energy = K.E. + P. E.
= \(\frac{e^2}{r}\) + (-\(\frac{e^2}{r}\))
= -\(\frac{e^2}{2r}\)