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05/10/2020 11:56 am
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The inversion temperature Ti (K) of hydrogen is (given van der Waal’s constants a and b are 0.244 atm L2 mol-2 and 0.027 L mol-1 respectively)
(a) 440
(b) 220
(c) 110
(d) 330
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05/10/2020 12:00 pm
(b) 220
Explanation:
Gases become cooler during Joule Thomson’s expansion only if they are below a certain temperature known as inversion temperature (Ti). The inversion temperature is characteristic of each gas and is given by
Ti = 2a/bR
where R is gas constant
Given a = 0.244 atm L2 mol-2
b = 0.027 L mol-1
R = 0.0821 L atm deg-1 mol-1
∴ Ti = 2 x 0.244/0.027 x 0.0821
= 220K