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05/10/2020 12:22 pm
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Cyclopropane and oxygen at partial pressures 170 torr and 570 torr respectively are mixed in a gas cylinder. What is the ratio of the number of moles of cyclopropane to the number of moles of oxygen (nC3H6 /nO2)?
(a) 170 x 42/570 x 32 = 0.39
(b) (170/42)/(170/42 + 570/32)≈ 0.19
(c) 170/740 = 0.23
(d) 170/570 = 0.30
1 Answer
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05/10/2020 12:25 pm
(d) 170/570 = 0.30
Explanation:
By ideal gas equation
P1V = n1RT
n1 ∝ P1 and n2 ∝ P2
n1/n2 = P1/P2 => n1/n2 = 170/570 = 0.30