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Two vessels containing gases A and B are interconnected as shown in the figure. The stopper is opened, the gases are allowed to mix homogeneously.

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Two vessels containing gases A and B are interconnected as shown in the figure. The stopper is opened, the gases are allowed to mix homogeneously. The partial pressures of A and B in the mixture will be, respectively

(a) 8 and 5 atm

(b) 9.6 and 4 atm

(c) 4.8 and 2 atm

(d) 6.4 and 4 atm

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(c) 4.8 and 2 atm

Explanation:

Moles of A, (nA) = \(\frac{P_AV_A}{RT}\)

= \(\frac{8 \times 12}{RT}\)

= \(\frac{96}{RT}\)

Moles of B, (nB) = \(\frac{P_BV_B}{RT}\)

= \(\frac{8 \times 5}{RT}\)

= \(\frac{40}{RT}\)

Total pressure × total volume = (nA + nB) × RT

p (12 + 8) = \(\frac{1}{RT}\)(96 + 40)RT

P = 6.8

Partial pressure of A = P × mole fraction of A = 6.8

= \(\Big(\frac{\frac{96}{RT}}{\frac{96+40}{RT}} \Big)\)

= 4.8 atm

Partial pressure of B = 6.8 - 4.8

= 2 atm.

This post was modified 3 years ago 2 times by Shivani siva
This post was modified 3 years ago 2 times by admin
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