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Oxidation of succinate ions produces ethylene and carbon dioxide gases. On passing 0.2 Faraday electricity through an aqueous solution of potassium succinate, the total volume of gases

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Oxidation of succinate ions produces ethylene and carbon dioxide gases. On passing 0.2 Faraday electricity through an aqueous solution of potassium succinate, the total volume of gases (at both cathode and anode) at STP (1 atm and 273 K) is :

(a) 8.96 L

(b) 4.48 L

(c) 6.72 L

(d) 2.24 L

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Correct answer: (a) 8.96 L

Explanation:

\(\overset{CH_2COO^-}{\overset{|}{CH_2COO^-}} + 2H_2O\) → \(\overset{CH_2}{\overset{||}{CH_2}}\) + CO2 + H2 + 2OH-

Total equivalent of 

C2H4 + CO2 + H2

= 0.2 + 0.2 + 0.2 = 0.6

Total moles of gases

= \(\frac{0.2}{2}\) + \(\frac{0.2}{1}\) + \(\frac{0.2}{2}\)

= 0.4

V = \(\frac{nRT}{2}\) = \(\frac{0 .4 \times 0.0821 \times 273}{1}\)

= 8.96 L

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