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States of Matter
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08/09/2021 8:14 pm
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Equal masses of methane and oxygen are mixed in an empty container at 25°C. The fraction of the total pressure exerted by oxygen is
(a) \(\frac{1}{2}\)
(b) \(\frac{2}{3}\)
(c) \(\frac{1}{3}\) x \(\frac{273}{298}\)
(d) \(\frac{1}{3}\)
1 Answer
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08/09/2021 8:21 pm
Correct answer: \(\frac{1}{3}\)
Explanation:
Let the mass of methane and oxygen = m gm.
Mole fraction of O2
= \(\frac{Moles\;of\;O_2}{Moles \; of\;O_2 + Moles\;of\;CH_4}\)
= \(\frac{\frac{m}{32}}{\frac{m}{32}+ \frac{m}{16}}\)
= \(\frac{\frac{m}{32}}{\frac{3m}{32}}\)
= \(\frac{1}{3}\)
Partial pressure of O2 =
Total pressure × mole fraction of O2,
PO2 = P x \(\frac{1}{3}\) = \(\frac{1}{3}\)P