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12/09/2021 11:53 am
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Cyclopropane and oxygen at partial pressures 170 torr and 570 torr respectively are mixed in a gas cylinder. What is the ratio of the number of moles of cyclopropane to the number of moles of oxygen (nC3H6/nO2)?
(a) \(\frac{170 \times 42}{570 \times 32}\) = 0.39
(b) \(\frac{170}{42}\)/\(\Big(\frac{170}{42}+\frac{570}{32}\Big)\)≈ 0.19
(c) \(\frac{170}{740}\) = 0.23
(d) \(\frac{170}{570}\) = 0.30
1 Answer
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12/09/2021 11:58 am
Correct answer: \(\frac{170}{570}\) = 0.30
Explanation:
By ideal gas equation,
P1V = n1RT
n1 ∝ P1 and n2 ∝ P2
\(\frac{n_1}{n_2}\) = \(\frac{P_1}{P_2}\)
⇒ \(\frac{n_1}{n_2}\) = \(\frac{170}{570}\)
= 0.30