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08/09/2021 9:36 pm
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A neon-dioxygen mixture contains 70.6 g O2 and 167.5 g neon. If pressure of the mixture of gases in the cylinder is 25 bar. What is the partial pressure of O2 and Ne in the mixture respectively?
(a) 5.25 bar, 10 bar
(b) 19.75 bar, 5.25 bar
(c) 19.75 bar, 10 bar
(d) 5.25 bar, 19.75 bar
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08/09/2021 9:43 pm
Correct answer: (d) 5.25 bar, 19.75 bar
Explanation:
Number of moles of O2
= \(\frac{70.6g}{32g\;mol^{-1}}\) = 2.21 mole
Number of moles of Ne
= \(\frac{167.5g}{20g\;mol^{-1}}\) = 8.375 mole
Mole fraction of O2
= \(\frac{2.21}{2.21 + 8.375}\) = 0.21 mole
Mole fraction of Ne = 1 – 0.21 = 0.79
Partial pressure of a gas = Mole fraction × total pressure
Partial pressure of O2 = 0.21 × 25 = 5.25 bar
Partial pressure of Ne = 0.79 × 25 = 19.75 bar
This post was modified 3 years ago by Shivani siva