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Squares and Square Roots
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08/08/2021 11:46 am
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Find the smallest square number that is divisible by each of the numbers 8, 15 and 20.
1 Answer
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08/08/2021 1:11 pm
L.C.M of 8, 15 and 20 is (2×2×5×2×3) 120.
120 = 2 × 2 × 3 × 5 × 2
= (2 × 2) × 3 × 5 × 2
Here, 3, 5 and 2 cannot be paired.
∴ We will multiply 120 by (3 × 5 × 2) 30 to get perfect square.
Hence, the smallest square number divisible by 8, 15 and 20
= 120 × 30 = 3600